Tuesday, March 5, 2013

9.6-9.7, due on March 6

Theorem 9.11 quickly made sense.

Let f : A → B be a function. Then the inverse relation f−1 is a function from B to A if
and only if f is bijective. Furthermore, if f is bijective, then f−1 is also bijective.

The proof got a little jumbled for me.  In order to show that f-1 is a function, I suppose it is as easy as showing that f is one-to-one and onto.  I am confused as to why the proof continued with the converse.  For me, it has been helpful to follow a proof pattern when writing my own proofs.  If I have a guide of what needs to be shown, it is manageable.  I don't quite get the pattern of this proof and would need a clarification as to why it was set up the way it was.

I remember learning about permutations in a statistics class I had last semester.  Pretty interesting.  That part of the material made sense to me, although I remember getting a little tripped up with permutations as they became more complicated.  It is interesting to note that permutations are bijective functions and have inverses.  I didn'onsider that really when I learned about them last semester, but it definitely makes sense.  I look forward to Chapter 13 when they are discussed in more detail.

No comments:

Post a Comment